How to compare transform?

Bat_boy

I'm making a game and I'm comparing transform with an if statement but its not working. if transform.origin == Vector3(-0.5, -0.6, -0.1): print("Ready") But it never prints(I even checked the position but when it became that it didn't nothing happened).

Megalomaniak

This discussion was caught in the moderation queue since you have not confirmed your account yet.

Upon creating your account you should have received an account verification email. The confirmation email may have been incorrectly flagged as spam, so please also check your spam filter. Without confirming your account, future posts may also be caught in the moderation queue. You can resend a confirmation email when you log into your account if you cannot find the first verification email.

If you need any help, please let us know! You can find ways to contact forum staff on the Contact page. Thanks! :smile:

cybereality

No, that will never work due to floating point inaccuracy. Also, it's not a good idea to compare values like that directly. Usually you want to check for ranges, like if a distance is more than a certain threshold, but never direct equality. You can read more here: https://floating-point-gui.de/

cybereality

You could do something like:

if transform.origin.distance_to(Vector3(-0.5, -0.6, -0.1)) < 0.01:
    print("almost the same")

But I would still feel like this is a bad design and not a robust way to do it.

TwistedTwigleg

You could use the is_equal_approx function to check if the vectors are close while avoiding the floating point precision. I'm not sure how close they would have to be to be considered equal though, nor what the performance impact would be.

Using a solution like @cybereality showed with distance_to is a good solution for more control over what range of distances are considered equal. You can also get a bit more performance out of it by using distance_squared_to instead of distance_to:

if transform.origin.distance_squared_to(Vector3(-0.5, -0.6, -0.1)) < 0.01:
	print ("almost the same")