How do I prevent a function from executing when it's already executed?

Sosasees

To fix this bug (YouTube Video), I must make sure that the die() function of the player script only gets executed once and not multiple times at once.

This is the die() function that must not execute multiple times at once:

func die():
	print ("DIE!: ", stepify(dieTimer, 0.01), " / ", dieTime)
	alive = false
	if alive == false:
		speed = 0; jumpHeight = 0
		$JumpSound.volume_db = -80
		if ($DeathSound.playing == false):
			$DeathSound.play()
		if dieTimer == dieTime or dieTimer > dieTime:
			# warning-ignore:return_value_discarded
			get_tree().reload_current_scene()

How do I make sure that the function only gets executed one time at a time?

vinpogo

I understand that the problem is that the function is executed multiple times? i see multiple solutions: 1. control calling of the function (outside of player scene) 2. control execution of function (inside player scene)

for 1.: i would check if player is alive, and only call the function if player is alive

for 2.: maybe add this as the first line of the function? if not alive: return OR only set alive = false inside your function. in your _process function you can then do if not alive: die(); set_process(false);

EDIT: missing code piece

Sosasees

@vinpogo Thanks very much! The first method didn't work, but the second did. Part of the die() function is now in _process():

func _process(delta):
[...]
	if !alive:
		dieTimer += delta
		if ($DeathSound.playing == false):
			$DeathSound.play()
		if dieTimer > dieTime - 0.01:
			# warning-ignore:return_value_discarded
			get_tree().reload_current_scene()
[...]
func die(): 
	#print ("DIE!: ", stepify(dieTimer, 0.01), " / ", dieTime)
	alive = false
	speed = 0; jumpHeight = 0
	$JumpSound.volume_db = -80
	#The rest is done in ```_process()``` @ ```if !alive```

I'll credit your Godot Forums Profile and Answer if you don't disagree by tomorrow.